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4+23.5x-4.9x^2=0
a = -4.9; b = 23.5; c = +4;
Δ = b2-4ac
Δ = 23.52-4·(-4.9)·4
Δ = 630.65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23.5)-\sqrt{630.65}}{2*-4.9}=\frac{-23.5-\sqrt{630.65}}{-9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23.5)+\sqrt{630.65}}{2*-4.9}=\frac{-23.5+\sqrt{630.65}}{-9.8} $
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